05 Chemical Bonds
06 Acids, Bases and Salts
2 of 3

5.2.2 Ionic Bonding

Ionic Bonding

  1. Ionic bonds are formed by one atom transferring electrons to another atom to form ions. 
  2. Ions are atoms, or groups of atoms, which have lost or gained electrons.
  3. The atom losing electrons forms a positive ion (a cation) and is usually a metal.
  4. The atom gaining electrons forms a negative ion (an anion) and is usually a non-metallic element.
  5. Ions of opposite charge will attract one another by strong electrostatic force, thus creating an ionic bond.
  6. The ionic bond is also known as electrovalence bond.

Example: Ionic Bonding between Group 1 Metals and Group 17 Elements

  1. The figure above shows the illustration of the formation of the ionic bond between a sodium atom (group 1 metal) and a chlorine atom (group 17 element).
  2. The electron arrangement of the sodium atom is 2.8.1, which is not octet and hence not stable.
  3. To achieve octet electrons arrangement, the sodium atom donates/release one electron and form sodium ion.
  4. The electron arrangement of the chlorine atom is 2.8.7, which is also not octet and hence not stable, too.
  5. To achieve octet electrons arrangement, the chlorine atom receives one electron from the sodium atom and form a chloride ion.
  6. The sodium ion and the chloride ion carry opposite charges, hence they attract each other and form an ionic bond between each other.

 

Example: Ionic Bonding between Group 2 Metals and Group 17 Elements
  1. The figure above shows the illustration of the formation of the ionic bond between two potassium atoms (group 1 metal) and an oxygen atom (group 16 element).
  2. The electron arrangement of the potassium atom is 2.8.8.1, which is not octet and hence not stable.
  3. To achieve octet electrons arrangement, the potassium atom donates/release one electron and form potassium ion.
  4. The electron arrangement of oxygen atom is 2.6, which is also not octet and hence not stable, too.
  5. To achieve the octet electrons arrangement, the oxygen atom receives two electrons from potassium atoms and form an oxide ion.
  6. The potassium ions and the oxide ion carry opposite charges, hence they attract each other and form two ionic bond between the ions.

Example: Ionic Bonding between Group 2 Metals and Group 16 Elements

  1. The figure above shows the illustration of the formation of the ionic bond between a calcium atom (group 2 metal) and an oxygen atom (group 16 element).
  2. The electron arrangement of the calcium atom is 2.8.8.2, which is not octet and hence not stable.
  3. To achieve octet electrons arrangement, the potassium atom donates/release two electrons and form calcium ion.
  4. The electron arrangement of oxygen atom is 2.6, which is also not octet and hence not stable, too.
  5. To achieve the octet electrons arrangement, the oxygen atom receives two electrons from the calcium atom and form an oxide ion.
  6. The calcium ion and the oxide ion carry opposite charge, hence they attract each other and form an ionic bond between each other.

Predicting the Formula of Ionic Compound

  1. We can predict the charge of the ions formed from an element base on the group of the element.
  2. From the charge, we can then write the formula of the ionic compound formed.
  3. In short, we can predict the formula of an ionic compound if we know the group (in the periodic table) of the elements in the compound.
  4. The table below shows the formula of the ionic compounds formed by the elements from a different group in a periodic table.
Elements
Formula of Ionic Compound
Examples
Atoms of Metal, MAtoms of Non-Metal, N
Group 1
Group 15
 M3N
Na3N
Group 1
Group 16
M2N
K2O
Group 1
Group 17
MN
LiCl
Group 2
Group 15
M3N2
Ca3N2
Group 2
Group 16
MN
MgO
Group 2
Group 17
MN2
BaBr2
Group 13
Group 15
MN
AlN
Group 13
Group 16
M2N3
Al2O3
Group 13
Group 17
MN3
AlI3